Q.
The freezing point of a $0.08$ molal aqueous solution of $NaHSO _{4}$ is $-0.372^{\circ} C$. The dissociation constant for the following reaction is: $\left(K_{f}\right.$ for $\left.H _{2} O =1.86\, K . kg / mol \right)$
$HSO _{4}^{-} \longrightarrow H ^{+}+ SO _{4}^{2-}$
Solutions
Solution: