1. Tardigrade
  2. Question
  3. Chemistry
  4. The freezing point of a 0.01 m aqueous glucose solution at 1 atmosphere is -0.18° C . To it, an addition of equal volume of 0.002 m glucose solution will produce a solution with freezing point of nearly

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Q. The freezing point of a 0.01 m aqueous glucose solution at 1 atmosphere is $ -0.18{}^\circ C $ . To it, an addition of equal volume of 0.002 m glucose solution will produce a solution with freezing point of nearly

AMUAMU 1999

Solution:

: Depression in freezing point of 0.01 M aqueous glucose solution $ =0.18{}^\circ C $ Here, $ \Delta {{T}_{f}}={{K}_{f}}\times m $ $ {{K}_{f}}=\frac{0.18}{0.01}=18 $ Molality of solution obtained by mixing equal volumes of 0.01 m and 0.002 m solution $ =\frac{0.01+0.002}{2}=\frac{0.012}{2}=0.006m $ For 0.006 m glucose solution, $ \Delta {{T}_{f}}=18\times 0.006=0.108{}^\circ C $ .