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Q.
The freezing point depression of $0.001 \,m \,K_{x}[Fe(CN)_{6}]$ is
$7.10 \times 10^{-3}\, K$ Determine the value of x. Given, $K_{f}= 1.86\, K\, kg\, mol^{-1}$ for water
Solutions
Solution:
$\Delta x=i \times K_{f} \times m $
$7.10\times10^{-3}=i\times1.86\times0.001$
$i=3.817$
$\alpha=\frac{i-1}{n-1}$
$1=\frac{3.817-1}{\left(x+1\right)-1}$
$x=2.817=3$
$\therefore $ Molecular formula of the compound is $K_{3} \left[Fe\left(CN\right)_{6}\right]$