1. Tardigrade
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  3. Chemistry
  4. The free energy and entropy change in kJ per mole when liquid water boils at 1 atmosphere are respectively (latent heat of water = 2.0723 kJ g-1)

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Q. The free energy and entropy change in $kJ$ per mole when liquid water boils at 1 atmosphere are respectively (latent heat of water $= 2.0723\, kJ\, g^{-1}$)

Thermodynamics

Solution:

$\Delta H_{vap}$ of water $= 2.0723 \times 18 = 37.30\, kJ\, mol^{-1}$
$\Delta S_{vap}=\frac{\Delta H_{vap}}{T_{b}}=\frac{37.30\, kJ\, mol^{-1}}{373\, K}=0.1\, kJ\, mol^{-1}\,K^{-1}$
$\Delta G_{vap}=\Delta H\left(kJ\, mol^{-1}\right)-T\left(K\right)\Delta S\left(kJ\, K^{-1}\, mol^{-1}\right)$
$=37.30-373\times0.1=0$