Question

The four quantum numbers of the valence electron of potassium are

• A. $4, 1, 0$ and $\frac{1}{2}$
• B. $4, 0, 1$ and $\frac{1}{2}$
• C. $4, 0, 0$ and +$\frac{1}{2}$
• D. $4, 1, 1$ and$\frac{1}{2}$

Answer 1

Answer: (C)

Atomic number of potassium is $19$ and hence electronic configuration will be $1s^{2},2s^{2}, 2p^{6}, 3s^{2}, 3p^{6}, 4s^{1}$ Hence for $4s^1$ electron value of Quantum number are
Principal quantum number $n = 4$
Azimuthal quantum number $l = 0$
Magnetic quantum number $m = 0$
Spin quantum number s = $+ 1/2$