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Q.
The four quantum numbers of the valence electron of potassium are :
EAMCETEAMCET 1998
Solution:
The electronic configuration of potassium (At. no. 19) is: $ 1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}},4{{s}^{1}} $ The valence electron is present in $ 4{{s}^{1}}. $ Hence, quantum numbers for $ 4{{s}^{1}} $ are : n (Principal quantum no.) = 4 $ l $ (Azimuthal quantum no.) = 0 Note: for s sub shell $ l=0 $ for p sub shell $ l=1 $ for d sub shell $ l=2 $ for $ f $ sub shell $ l=3 $ m (magnetic quantum no.) = 0 The value of m depends upon $ l. $ s (spin quantum no.) $ =+\frac{1}{2}. $