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Chemistry
The formula of sodium nitroprusside is
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Q. The formula of sodium nitroprusside is
The d-and f-Block Elements
A
$Na _{4}\left[ Fe ( CN )_{5} NO _{2}\right]$
17%
B
$Na _{2}\left[ Fe ( CN )_{5} NO ^{+}\right]$
83%
C
$NaFe \left[ Fe ( CN )_{6}\right]$
0%
D
$Na _{2}\left[ Fe ( CN )_{6} NO _{2}\right]$
0%
Solution:
Correct answer is (b) $Na _{2}\left[ Fe ( CN )_{5} NO ^{+}\right]$