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Chemistry
The formal oxidation numbers of Cr and Cl in the ions Cr2O72- and ClO3-, respectively are
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Q. The formal oxidation numbers of $Cr$ and $Cl$ in the ions $Cr_2O_7^{2-}$ and $ClO_3^-$, respectively are
KVPY
KVPY 2018
Chemical Bonding and Molecular Structure
A
+ 6 and +7
B
+7 and +5
C
+6 and +5
D
+8 and +7
Solution:
In $Cr_2O_7^{2-}$
Let the oxidation state of $Cr$ be $x$
$\therefore 2(x) + 7 (-2 ) = - 2$
$2x - 14 = - 2$
$2x = 12$
$x = + 6$
In $ClO_3^-$,
Let the oxidation state of $Cl$ be $x$
$\therefore 1(x) + 3 (-2 ) = - 1$
$x - 6 = - 1$
$x = + 5$