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Q. The force-time (F-t) graph for linear motion of a body initially at rest is shown in figure. The segments shown are circular, the linear momentum gained in $4 s$ isPhysics Question Image

Laws of Motion

Solution:

We know that,
$F \Delta t = m \Delta v$
i.e., impulse from 0 to $4 s =$ linear momentum gained in $4 s$
$=$ area enclosed by graph from 0 to $4 s$
$=\frac{\pi r^{2}}{2} \quad(r=2)$
$=2 \pi N - s ^{1}$