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Q.
The force constant of a wire is $k$ and that of another wire of the same material is $2 k$. When both the wires are stretched, then work done is
Mechanical Properties of Solids
Solution:
Work done in stretching the wire
$W=\frac{1}{2} \times $ force constant $\times x^{2}$
For first wire, $W_{1}=\frac{1}{2} \times k x^{2}=\frac{1}{2} k x^{2}$
For second wire, $W_{2}=\frac{1}{2} \times 2 k \times x^{2}=k x^{2}$
Hence,
$W_{2}=2 W_{1}$