1. Tardigrade
  2. Question
  3. Physics
  4. The forbidden energy gap in Ge is 0.72 eV. The maximum wavelength of radiation that will generate an electron hole pair is approximately equal to x angstrom. Find (x/10). Round off answer to perfect integer. (Given: h c=12400 eV mathringA )

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The forbidden energy gap in $Ge$ is $0.72\, eV$. The maximum wavelength of radiation that will generate an electron hole pair is approximately equal to $x$ angstrom. Find $\frac{x}{10}$. Round off answer to perfect integer. (Given: $h c=12400\,eV\,\mathring{A}$ )

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

To create hole-electron pair,
$0.72=\frac{h c}{\lambda} $
$\Rightarrow \lambda=\frac{12400}{0.72}=17222 \mathring{A}$