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Mathematics
The foot of perpendicular drawn from point (1,2) on the line L is (2,3), then equation of line L is
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Q. The foot of perpendicular drawn from point $(1,2)$ on the line $L$ is $(2,3)$, then equation of line $L$ is
Straight Lines
A
$x+y-3=0$
17%
B
$x+y-5=0$
51%
C
$x+y+5=0$
17%
D
$2 x+y-5=0$
14%
Solution:
Slope of line $L$ is $=-1$ and its equation is $y-3=-1(x-2)$