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Q. The following reactions show the $ H_{2}O_{2} $ behaviour in I and II reactions as:
I. $ PbS(s) + 4 H_{2}O_{2} (aq) \to PbSO_{4}(s) + 4H_{2}O(l) $
II. $ HOCl + H_{2}O_{2} \to H_{3}O^{+} + Cl^{-} + O_{2} $

AMUAMU 2018Hydrogen

Solution:

Hydrogen peroxide, $H_{2}O_{2}$ oxidises lead sulphide, $PbS (s)$ to lead sulphate, $PbSO_{4} (s)$ in acidic medium
$\underset{\text{Black}}{{PbS(s)}}+4H_{2}O_{2}(aq) \to\underset{\text{white}}{{PbSO_{4}}(s)} + 4H_{2}O(l)$
It reacts with hypochlorous acid, $HOCl$ to produce water, oxygen and hydrochloric acid, showing oxidising action in acidic medium
$HOCl+H_{2}O_{2} \to H_{3}O^{+}+Cl^{-}+O_{2}$