Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The following reaction
$\text{R} - \left(\text{CH}\right)_{\text{2}} \left(\text{CH}\right)_{\text{2}} \overset{\text{+}}{\text{N}} \left(\left(\text{(CH}\right)_{\text{3}} \text{)}\right)_{\text{3}} \left(\text{OH}\right)^{-} \overset{\text{Δ}}{ \rightarrow } \text{RCH} \, \text{=} \, \left(\text{CH}\right)_{\text{2}} \left(\text{+N(CH}\right)_{\text{3}} \left(\text{)}\right)_{\text{3}} \, \text{+} \, \left(\text{H}\right)_{\text{2}} \text{O}$ is called

NTA AbhyasNTA Abhyas 2022

Solution:

Trialkyl ammonium hydroxide undergoes Hoffmann elimination to give less substituted alkene. Elimination of more acidic $\beta $ -H occurs from that $\beta $ -carbon, which is joined to largest number of hydrogens. Thus, elimination of H occurs opposite to that of Saytzeff rules.
Solution