Question

The following equation is the Arrhenius equation, $ k = Ae^{-E_a/RT} $ , where $ E_a $ is the minimum energy molecules must possess in order to react to form a product, $ k $ is the rate constant, $ A $ is the frequency factor, $ R $ is the gas constant and $ T $ is the Kelvin temperature. Under normal circumstances, the Arrhenius plot is obtained by plotting

• A. logarithm of the inverse of rate constant $ 1/k $ , versus the inverse temperature $ 1/T $
• B. logarithm of the rate constant $ k $ , versus the temperature $ T $
• C. logarithm of the rate constant $ k $ , versus the inverse temperature $ 1 /T $
• D. logarithm of the inverse of rate constant $ 1/k $ , versus the temperature $ T $

Answer 1

Answer: (C)

$k=Ae^{-E_{a}/RT}$
Taking log on both sides
$log_{10} \, k=log_{10} \,A-\frac{E_{a}}{2.303R}\left(\frac{1}{T}\right)$
Logarithm of $k$ is plotted against $(1/T)$ to obtain Arrhenius plot