Q.
The following data gives the distribution of height of students :
Height (in cm)
160
150
152
161
156
154
155
Number of students
12
8
4
4
3
3
7
The median of the distribution is
| Height (in cm) | 160 | 150 | 152 | 161 | 156 | 154 | 155 |
| Number of students | 12 | 8 | 4 | 4 | 3 | 3 | 7 |
Statistics
Solution:
Arranging the data in ascending order of magnitude, we obtain
Height (in cm)
150
152
154
155
156
160
161
Number of students
8
4
3
7
3
12
4
Cumulative
frequency
8
12
15
22
25
37
41
Here, total number of items is 41 , which is an odd number.
Hence, the median is $\frac{41+1}{2}$ th $=21$ st item.
From cumulative frequency table, we find that median i.e. 21st item is 155
| Height (in cm) | 150 | 152 | 154 | 155 | 156 | 160 | 161 |
| Number of students | 8 | 4 | 3 | 7 | 3 | 12 | 4 |
| Cumulative frequency | 8 | 12 | 15 | 22 | 25 | 37 | 41 |