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Q.
The following data are obtained from the decomposition of a gaseous compound
The order of the reaction is
Chemical Kinetics
Solution:
$\frac{\left( t _{1 / 2}\right)_{1}}{\left( t _{1 / 2}\right)_{2}}=\frac{80}{113}=\left( p _{2} / p _{1}\right)^{ n -1}$
Here $p _{2}, p _{1}$ are the initial pressures
$\frac{80}{113}=\left(\frac{0.8}{1.6}\right)^{ n -1}$ Taking logarithms,
$\log 0.7=( n -1) \log 0.5$
On solving, $n =1.5$
