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Q. The following conversion can be obtained by using

$ \underset{\text { (excess) }}{\mathrm{NH}_3} \stackrel{?}{\rightarrow} \mathrm{N}_2 \mathrm{H}_4 $

NTA AbhyasNTA Abhyas 2020The p-Block Elements - Part2

Solution:

$2 \, \underset{\text{excess}}{\text{NH}_{\text{3}}} \, \text{+} \, \text{NaOCl} \rightarrow \text{N}_{\text{2}} \text{H}_{\text{4}} \, \text{+} \, \text{NaCl} \, \text{+} \, \text{H}_{\text{2}} \text{O}$