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Q.
The following configuration of gates is equivalent to:-
NTA AbhyasNTA Abhyas 2022
Solution:
The above circuit is the combination of $OR$ gate, $NAND$ gate, and $AND$ gate. So, the net output voltage is
$Y=\left(\right.A+B\left.\right)\cdot \left(\right.\bar{A . B}\left.\right)$
$=\left(\right.A+B\left.\right)\cdot \left(\right.\bar{A}+\bar{B}\left.\right)$
$Y=A\cdot \bar{B}+\bar{A}\cdot B\left(\right.XOR\left.\right)$