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Q. The following configuration of gate is equivalent toPhysics Question Image

Punjab PMETPunjab PMET 2007Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

$Y=(A+B) \cdot \overline{A B}$
The given output equation can also be written as
image
$Y=(A+B) \cdot(\bar{A}+\bar{B})$ (De Morgan's theorem)
$=A \bar{A}+A \bar{B}+B \bar{A}+B \bar{B}$
$=0+A \bar{B}+\bar{A} B+0=\bar{A} B+A \bar{B}$
This is the expression for XOR gate.