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Q. The focal length of the objective of a telescope is $60\, cm$. To obtain a magnification of $20$ , the focal length of the eye piece should be

Ray Optics and Optical Instruments

Solution:

In normal adjustment,
$ M=\frac{f_0}{f_e}=20, f_e=\frac{f_0}{20}=\frac{60}{20}=3\, cm $