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Q. A plano-convex lens is made of refractive index of $1.6 .$ The radius of curvature of the curved surface is $60\, cm$. The focal length of the lens is

KCETKCET 2010Ray Optics and Optical Instruments

Solution:

Here, $ \frac{1}{f}=(\mu-1)\left[\frac{1}{R_{1}}-\frac{1}{R_{2}}\right]$
$ \frac{1}{f}=(1.6-1)\left[\frac{1}{60}-\frac{1}{\infty}\right]=\frac{1}{100} $
$ \Rightarrow f=100\, cm $