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Q. The first two terms of a geometric progression add upto 12. The sum of the third and the fourth terms is 48 . If terms of the geometric progression are alternately positive and negative, then the first term is

Sequences and Series

Solution:

Since, $a+a r=a(1+r)=12 ....$(i)
and $ a r^2+a r^3=a r^2(1+r)=48 ....$(ii)
From Eqs. (i) and (ii), we get
$r^2=4 \Rightarrow r=-2$
(since the G.P. is in alternate sign, so we take negative value)
On putting the value of $r$ in Eq. (i), we get $a=-12$