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  4. The first ionization potential of Na is 5.1eV . The value of electron gain enthalpy of Na+ will be

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Q. The first ionization potential of $Na$ is $5.1eV$ . The value of electron gain enthalpy of $Na^{+}$ will be

NTA AbhyasNTA Abhyas 2022

Solution:

Ionization energy = 5.1 eV
Electron gain enthalpy = negative value of ionization energy = - 5.1 eV
As electron gain enthalpy is the energy released when an electron is added to the isolated gaseous atom so it is exothermic by nature.