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Q. The first ionisation potential of $Na$ is $5.1\, eV$. The value of electron gain enthalpy of $Na^+$ will be

JEE MainJEE Main 2013Classification of Elements and Periodicity in Properties

Solution:

$Na \longrightarrow Na^+ + e^- \,$ First $\, IE$
$Na^+ + e^- \longrightarrow Na$
Electron gain enthalpy of $Na^+$ is reverse of (IE) Because reaction is reverse so
$ \Delta H (eq) = - 5.1 \, eV$