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Q. The first emission line in the atomic spectrum of hydrogen in the Balmer series appears at

Structure of Atom

Solution:

For Balmer $n_1 = 2$ and $n_2 = 3; v$
$= R \left(\frac{1}{2^{2}} - \frac{1}{3^{2}}\right) = \frac{5R}{36} cm^{-1}$