Question

The figure shows the potential energy function $ U(x) $ of a system in which a particle is in one-dimensional motion. Arrange regions $ AB $ , $ BC $ , $ CD $ and $ DE $ according to the magnitude of thefore on tho particle in decreasing order

• A. $ BC $ , $ DE $ , $ AB $ , $ CD $
• B. $ BC $ , $ AB $ , $ CD $ , $ DE $
• C. $ AB $ , $ CD $ , $ BC $ , $ DE $
• D. $ CD $ , $ AB $ , $ DE $ , $ BC $

Answer 1

Answer: (A)

Relation between force and potential energy is given by
$F\left(X\right) = \frac{-dU\left(X\right)}{dx} = -$ (slope of graph)
From graph,
In case of $(i), \frac{dU}{dx} $ is maximum
$\Rightarrow - \frac{dU}{dx} $ is minimum
In $BC, \frac{dU}{dx} = 0$
$\Rightarrow F = 0$
If we compare $ - (\frac{dU}{dx})$ of $DE$ $AB$ then magnitude of force of $DE$ is greater then $B$.