Question

The figure shows the P-V plot of an ideal gas taken through a cycle $ABCDA$. The part $ABC$ is a semi-circle and $CDA$ is half of an ellipse. Then,

• A. the process during the path $A \rightarrow B$ is isothermal
• B. heat flows out of the gas during the path $B \rightarrow C \rightarrow D$
• C. work done during the path $A \rightarrow B \rightarrow C$ is zero
• D. positive work is done by the gas in the cycle $ABCDA$

Answer 1

Answer: (B), (D)

$\Delta Q=\Delta U+W$
For process $B \rightarrow C \rightarrow D$
$\Delta U$ is negative as well as $W$ is also negative