Q.
The figure shows four identical conducting plates each of area $A$. The separation between the consecutive plates is equal to $L$. When both the switches are closed, the charge present on the upper surface of the lowest plate from the top is written as $\frac{x V_{0} \varepsilon_{0} A}{L}$. What is the value of $x ?$
(Treat symbols as having usual meaning.)
Electrostatic Potential and Capacitance
Solution: