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Q. The figure shows a meter-bridge circuit where $X=12 \,\Omega$ and $R=18\, \Omega$. The jockey $J$ is at the null point. If $R$ is made $8\, \Omega$, through what distance will the jockey $J$ have to be moved to obtain null point again?Physics Question Image

Current Electricity

Solution:

$\frac{A J}{100-A J}=\frac{X}{R}=\frac{12}{18}$
$ \Rightarrow A J=40 \,cm$
After changing $R$ :
$\frac{A J'}{100-A J'}=\frac{12}{8}$
$ \Rightarrow A J'=60 \,cm$
Shifting: $A J'-A J=20\, cm$