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Q. The figure shows a fixed incline plane on which a plank is being pulled upwards such that the centre $C$ of the solid cylinder remains at rest with respect to ground. If no slipping takes place between the cylinder and the plank, then the acceleration of the plank is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Linear acceleration of cylinder is zero, i.e.,
$mg \, sin \, \theta =f$ ( here $f$ = frictional force upwards )
Angular acceleration about the centre $\alpha =\frac{\tau}{I}$
or $\alpha =\frac{\text{fR}}{\frac{1}{2} \text{mR}^{2}}=\frac{\text{2f}}{\text{mR}}$
or $\alpha =\frac{\text{2mg sin} \theta }{\text{mR}}=\frac{\text{2g sin} \theta }{\text{R}}$
For no slipping between cylinder and plank
$a=\text{R}\alpha =\text{2g sin}\theta $