Q.
The figure shows a combination of two NOT gates and a NOR gate.
The combination is equivalent to a
AIEEEAIEEE 2012Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
Truth table is as shown :
A
B
$\bar{A}$
$\bar{B}$
$\bar{A} + \bar{B}$
$\overline{\bar{A} + \bar{B}}$
0
0
1
1
1
0
0
1
1
0
1
0
1
0
0
1
1
0
1
1
0
0
0
1
Thus the combination of two NOT gates and one NOR gate is equivalent to a AND gate.
| A | B | $\bar{A}$ | $\bar{B}$ | $\bar{A} + \bar{B}$ | $\overline{\bar{A} + \bar{B}}$ |
|---|---|---|---|---|---|
| 0 | 0 | 1 | 1 | 1 | 0 |
| 0 | 1 | 1 | 0 | 1 | 0 |
| 1 | 0 | 0 | 1 | 1 | 0 |
| 1 | 1 | 0 | 0 | 0 | 1 |