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  4. The figure shown below is a screw gauge. When the circular scale division matches the main scale at 43, the 6.5 mm mark on the main scale is just visible. The main scale has (1/2) mm marks. In complete rotation, the screw advances by (1/2) mm and circular scale has 50 divisions. The reading of the screw gauge is <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-ixngjjzdhbxbxfcd.jpg />

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Q. The figure shown below is a screw gauge. When the circular scale division matches the main scale at $43$, the $6.5\,mm$ mark on the main scale is just visible. The main scale has $\frac{1}{2}$ $mm$ marks. In complete rotation, the screw advances by $\frac{1}{2}$ $mm$ and circular scale has $50$ divisions. The reading of the screw gauge is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Object thickness $=6.5\, mm +43 \frac{1 / 2 \,mm }{50}=6.93 \,mm$