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Q. The factorization of $128-32 x+2 x^2$ is

Polynomials, LCM and HCF of Polynomials

Solution:

$ 128-32 x+2 x^2$
$ =2 x^2-32 x+128=0$
$ =2 x^2-16 x-16 x+128=0 $
$ =2 x(x-8)-16(x-8)=0$\
$ =(2 x-16)(x-8)$
$ =2(x-8)^2$