Question

The extremities of the base of an isosceles triangle $A B C$ are the points $A (2,0)$ and $B (0,1)$. If the equation of the side $A C$ is $x=2$ then the slope of the side $B C$ is

• A. $\frac{3}{4}$
• B. $\frac{4}{3}$
• C. $\frac{3}{2}$
• D. $\sqrt{3}$

Answer 1

Answer: (A)

$AB = BC$
$\therefore \sqrt{ k ^{2}}=\sqrt{4+( k -1)^{2}}$

$k ^{2}=4+ k ^{2}-2 k +1 $
$\therefore k =\frac{5}{2}$
$\therefore $ Slope of $BC =\frac{\frac{5}{2}-1}{2}=\frac{5-2}{4}=\frac{3}{4}$