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Q. The expression for Doppler's shift is given by
$\frac{\Delta v}{v}=\frac{v_{\text {radial }}}{c}$
[Consider the directions from observer to source as positive]
Here, $v_{\text {radial }}$ refers to

Wave Optics

Solution:

In Doppler's shift given by, $\frac{\Delta v}{v}=\frac{v_{\text {radial }}}{c}$ $\frac{\Delta v}{v}=$ fractional change in frequency
$v_{\text {radial }}=$ the component of the source velocity along the lin joining the observer to the source relative to the observer
$c=$ speed of light in vacuum $=3 \times 10^{8} ms ^{-1}$.