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Q. The excess pressure inside one soap bubble is three times that inside a second soap bubble, then the ratio of their surface areas is

KEAMKEAM 2008Mechanical Properties of Fluids

Solution:

Accordingly $ \frac{4T}{{{r}_{1}}}=3\times \frac{4T}{{{r}_{2}}} $
$ \Rightarrow $ $ \frac{{{r}_{1}}}{{{r}_{2}}}=\frac{1}{3} $
Ratio of surface areas
$ \frac{{{A}_{1}}}{{{A}_{2}}}=\frac{4\pi r_{1}^{2}}{4\pi r_{2}^{2}}=\frac{1}{9} $