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  4. The escape velocity from the earth is 11 kms-1. The escape velocity from a planet having twice the radius and same mean density as that of earth is

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Q. The escape velocity from the earth is $11 \,kms^{-1}$. The escape velocity from a planet having twice the radius and same mean density as that of earth is

AFMCAFMC 2012

Solution:

Escape velocity,
$v_{e}=\sqrt{\frac{2 G M}{R}}=R \sqrt{\frac{8}{3} \pi G \rho}$
$\therefore v_{e} \propto R$ if $\rho=$ constant
Since, the planet is having double radius in comparision to earth, therefore escape velocity becomes twice i.e., $22\, kms ^{-1}$.