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Q. The error in the measurement of radius of sphere is $0.3\%$, what is percentage error in the measurement of its volume?

ManipalManipal 2011

Solution:

Error in radius, $\frac{\Delta r}{r}=0.3 \%$
Volume of sphere $=\frac{4}{3} \pi r^{3}$
$\therefore $ Error in volume $=3 \times \frac{\Delta r}{r}$
$=(3 \times 0.3) \%=0.9 \%$