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  4. The equivalent weight of phosphoric acid ( H 3 PO 4) in the reaction, NaOH + H 3 PO 4 arrow NaH 2 PO 4+ H 2 O is

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Q. The equivalent weight of phosphoric acid $\left( H _{3} PO _{4}\right)$ in the reaction, $NaOH + H _{3} PO _{4} \rightarrow NaH _{2} PO _{4}+ H _{2} O$ is

Redox Reactions

Solution:

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Here $1$ mole of $NaOH$ reacts with $1 mole$ of $H _{3} PO _{4}$. Since substances react in the ratio of their gram equivalents; thus, $1 g$ equivalent weight of $NaOH$ reacts with $1 g$ equivalent weight of $H _{3} PO _{4}$. Therefore, equivalent weight of $H _{3} PO _{4}$ in this reaction is $98$ .