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  4. The equivalent weight of Mohrs salt is:

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Q. The equivalent weight of Mohrs salt is:

JIPMERJIPMER 1997

Solution:

The molecular weight of Mohrs salt $ (FeS{{O}_{4}}\cdot {{(N{{H}_{4}})}_{2}}S{{O}_{4}}\cdot 6{{H}_{2}}O) $ = 56+2 (32 + 64) + 2 (14 + 4) + 6 (18) = 56 +192 + 36 +108 = 392 $ \therefore $ Equivalent weight of reductant $ =\frac{\text{Mol}\text{.wt}\text{.}}{\text{increase}\,\text{in}\,\text{O}\text{.N}\text{.}}=\frac{392}{1}=392 $ ( $ \because $ $ F{{e}^{2+}} $ changes into $ F{{e}^{3+}} $ in its reactions)