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Chemistry
The equivalent weight of Mohr’s salt FeSO4. (NH4)2 SO4. 6H2O in redox change is equal to its
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Q. The equivalent weight of Mohr’s salt $FeSO_{4}. (NH_{4})_{2} SO_{4}. 6H_{2}O$ in redox change is equal to its
Redox Reactions
A
molecular weight/2
60%
B
atomic weight
0%
C
molecular weight/3
20%
D
molecular weight
20%
Solution:
Valence factor for $FeSO_{4} (NH_{4})_{2}SO_{4} . 6H_{2}O$