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Q.
The equivalent weight of $ MnSO_{4} $ is half of its molecular weight when it is converted to
Uttarkhand PMTUttarkhand PMT 2009
Solution:
$\overset{+2}{Mn}SO_4 \rightarrow \overset{+4}{Mn}O_2$
In this conversion, there is loss of two electrons, hence equivalent weight of $ MnSO_{4} $ is the half of its molecular weight.