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Q. The equivalent weight of $ MnSO_{4} $ is half of its molecular weight when it is converted to

Uttarkhand PMTUttarkhand PMT 2009

Solution:

$\overset{+2}{Mn}SO_4 \rightarrow \overset{+4}{Mn}O_2$
In this conversion, there is loss of two electrons, hence equivalent weight of $ MnSO_{4} $ is the half of its molecular weight.