1. Tardigrade
  2. Question
  3. Chemistry
  4. The equivalent weight of KMnO4 in alkaline medium is equal to:

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The equivalent weight of $ KMnO_{4} $ in alkaline medium is equal to:

BHUBHU 2006

Solution:

In alkaline medium
$\overset{+7}{2 KMnO _{4}}+2 KOH \longrightarrow \overset{+6}{2 K _{2} MnO _{4}}+ H _{2} O + O$
Change in oxidation number $=7-6=1$
Equivalent weight
$=\frac{\text { molecular weight }}{\text { change in oxidation number }}$
$=\frac{M}{1}=M$