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Q. The equivalent weight of $KIO_{3}$ in the reaction
$2Cr(OH)_{3} +4OH +KIO_{3} \to 2CrO^{2-}_{4} +5H_{2}O +KI$ is

Redox Reactions

Solution:

$\frac{Molecular\, weight}{3}$ Because in $KIO_{3}$, effective oxidation number is 3