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Q.
The equivalent weight of a solid element is found to be $9$. If the specific heat of this element is $ 1.05\,Jg\,K^{-1}, $ then its atomic weight is:
Uttarkhand PMTUttarkhand PMT 2004
Solution:
By using: Valency of an element
$=\frac{\text { Approximate weight }}{\text { Equivalent weight }}$
$=\frac{26.8 / \text { specific heat }}{\text { Equivalent weight }} $
$=\frac{26.8 / 1.05}{9}=2.835 \cong 3$
Now, by using Atomic weight $=$ Equivalent weight $\times$ valency
$=9 \times 3=27$