Thank you for reporting, we will resolve it shortly
Q.
The equivalent resistance between the points $A$ and $B$ will be (each resistance is $15 \Omega $ )
NTA AbhyasNTA Abhyas 2020Current Electricity
Solution:
The circuit can be shown as given below
The equivalent resistance between $A$ and $C$ .
$R_{D C}=\frac{15 \times \left(15 + 15\right)}{15 + \left(15 + 15\right)}$
$ \, \, \, =\frac{15 \times 30}{15 + 30}$
$ \, =\frac{15 \times 30}{45}=10\Omega $
Now, between $A$ and $B$ , the resistance of the upper part $ADCB,$
$R_{1}=15+10+15=40\Omega $
Between $A$ and $B$ , the resistance of the middle part $AOB$
$R_{2}=15+15=30\Omega $
Therefore, equivalent resistance between $A$ and $B$
$\frac{1}{R^{}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}$
$ \, \, \, =\frac{1}{40}+\frac{1}{30}+\frac{1}{15}$
$ \, \, \, =\frac{3 + 4 + 8}{120}$
$ \, \, \, =\frac{15}{120}$
$\Rightarrow \, \, R^{}=\frac{120}{15}=8\Omega $
