The equivalent circuit for the given electrical network is
This is a balanced Wheatstone bridge, so the arm containing $2 r$ not in use. So, we have
So, the equivalent resistance between $a$ and $b$ is
$ \frac{1}{r^{\prime}}=\frac{1}{2 r}+\frac{1}{2 r} $
$\Rightarrow r^{\prime}=\frac{2 r}{2}=r $