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  4. The equivalent resistance between points a and b of a network shown in figure is given by

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Q. The equivalent resistance between points $a$ and $b$ of a network shown in figure is given byPhysics Question Image

Current Electricity

Solution:

As $\frac{1}{R}=\frac{1}{R}+\frac{1}{R}+\frac{1}{R}=\frac{3}{R}$
image
$\therefore R_{N}=R+\frac{R}{3}=\frac{3 R+R}{3}=\frac{4}{3} R$