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Q.
The equivalent inductance between $A$ and $B$ is
Electromagnetic Induction
Solution:
The equivalent circuit diagram is as shown in the figure
Here, all the inductances are connected in parallel Hence, the equivalent inductance between $A$ and $B$ is
$\frac{1}{L_{AB}}=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}+\frac{1}{4}=\frac{4}{4}=1$
or $L_{AB}=1\,H$
